Match the polymers given in Column-$I$ with the type of linkage present in them given in Column-$II$.
Column-$I$ Column-$II$ $A$. Terylene $i$. Glycosidic linkage $B$. Nylon $ii$. Ester linkage $C$. Cellulose $iii$. Phosphodiester linkage $D$. Protein $iv$. Amide linkage $E$. $RNA$
| Column-$I$ | Column-$II$ |
| $A$. Terylene | $i$. Glycosidic linkage |
| $B$. Nylon | $ii$. Ester linkage |
| $C$. Cellulose | $iii$. Phosphodiester linkage |
| $D$. Protein | $iv$. Amide linkage |
| $E$. $RNA$ |
(A) (Terylene) contains ester linkages $(ii)$.
$B$ (Nylon) contains amide linkages $(iv)$.
$C$ (Cellulose) contains glycosidic linkages $(i)$.
$D$ (Protein) contains peptide linkages (a type of amide linkage,but in this context,it is distinct; however,based on the options provided,$D$ corresponds to amide linkage $iv$ if we consider the general structure,but typically $D$ is peptide. Given the options,$A-ii, B-iv, C-i, D-iv, E-iii$ is the mapping).
Correct matching: $A-ii, B-iv, C-i, D-iv, E-iii$.
$B$ (Nylon) contains amide linkages $(iv)$.
$C$ (Cellulose) contains glycosidic linkages $(i)$.
$D$ (Protein) contains peptide linkages (a type of amide linkage,but in this context,it is distinct; however,based on the options provided,$D$ corresponds to amide linkage $iv$ if we consider the general structure,but typically $D$ is peptide. Given the options,$A-ii, B-iv, C-i, D-iv, E-iii$ is the mapping).
Correct matching: $A-ii, B-iv, C-i, D-iv, E-iii$.
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| Item-$I$ | Item-$II$ |
|---|---|
| $a$. Natural rubber | $I$. $1,3-$butadiene $+$ styrene |
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| $c$. Buna$-N$ | $III$. Chloroprene |
| $d$. Buna$-S$ | $IV$. Isoprene |
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